Question

Hcf of (4*27*3125),(8*9*25*70) and (16*81*5*49) is:

Answer 1

Answer:

180

Step-by-step explanation:

Breaking down into factors, each number becomes.

4*27*3125 = 2 * 2 * 3 * 3 * 3 * 5 * 5 * 5 * 5 * 5

8 * 9 * 25 * 70 = 2 * 2 * 2 * 2 * 3 * 3 * 5 * 5 * 5 * 7

16 * 81 * 5 * 49 = 2 * 2 * 2 * 2* 3 * 3 * 3 * 3 * 5 * 7 * 7

The common factors across 3 numbers is shown above.

Thus HCF = 2 * 2 * 3 * 3 * 5  = 180