Question

HCF of 46 ,184 ,and ,230 by using division method​

Answer 1

Answer:

Given numbers are 46, 184, and,230

Applying Euclid's division lemma to 46 and 184, we get

46 = 46 × 1 + 0

184 = 46 × 4 + 0

The remainder at this stage is zero.

So, the divisor at this or the remainder at the previous stage i.e., 46 is the HCF of 46 and 184.

Also,

230 = 46 × 5 + 0

∴ HCF of 230 and 46 is 46

HCF (46, 184, 230) = 46

Hence, the required HCF of 46, 184 and 230 is 46.