Question

HCF of 48 , 80 and 64 I forgot to write hcf​

Answer 1

Answer:

378 is your answer.....

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Answer 2

In this problem, we are assuming we have to find the HCF of$48, 80, \ and\ 64$.

Q. Find the HCF of$48, 80, \ and\ 64$.

Given: The numbers are$48, 80, \ and\ 64$.

We have to find the HCF of the above numbers.

As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are$48, 80, \ and\ 64$.

First, we will find the factors of the above numbers.

The factors of 48 are: $1, 2, 3, 4, 6, 8, 12, 16, 24, 48$

The factors of 64 are: $1, 2, 4, 8, 16, 32, 64$

The factors of 80 are: $1, 2, 4, 5, 8, 10, 16, 20, 40, 80$

From the above, we can see that$16$ is the largest positive integer that divides each of the integers.

Then the greatest common factor is$16$.

Hence, we get,$HCF=16$