Question

HCF of 496 and 1116... Will anyone please explain it step by step​

Answer 1

Answer:

Since , 1116 > 496

We apply the division lemma to 1116 and 496→ 1116 = 496 × 2 + 124

Since the remainder 496 ≠ 0 , we apply division lemma to

496 and 124

→ 496 = 124 × 3 + 0

The reminder now become zero so our procedure stops

Since , the divisor at this stage is 124

∴ the HCF of 1116 and 496 is 124.

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