HCF of 5^2 x 3^2 and 3^5 x 5^3 is:
Answers
Answer:
225
Step-by-step explanation:
let 5^2 x 3^2 be "x"
let 3^5 x 5^3 be "y"
we know that HCF of two numbers "x" and "y" is equal to the product of the lowest powers of each common prime factor
x = 5² * 3²
y = 3⁵ * 5³
common prime factors in "x" and "y" are 3 and 5 ( 3 and 5 are present in prime factorisation of both "x" and "y" )
lowest power of 3 in the prime factorisation is 3² ( 3² < 3⁵ )
lowest power of 5 in the prime factorisation is 5² ( 5² < 5³ )
so HCF of "x" and "y" is 3² * 5²
= 9 * 25
= 225
therefore the HCF of 5^2 x 3^2 and 3^5 x 5^3 is 225
let 5^2 x 3^2 be "x"
let 3^5 x 5^3 be "y"
we know that HCF of two numbers "x" and "y" is equal to the product of the lowest powers of each common prime factor
x = 5² * 3²
y = 3⁵ * 5³
common prime factors in "x" and "y" are 3 and 5 ( 3 and 5 are present in prime factorisation of both "x" and "y" )
lowest power of 3 in the prime factorisation is 3² ( 3² < 3⁵ )
lowest power of 5 in the prime factorisation is 5² ( 5² < 5³ )
so HCF of "x" and "y" is 3² * 5²
= 9 * 25
= 225
therefore the HCF of 5^2 x 3^2 and 3^5 x 5^3 is 225