Question

hcf of 548,12,45,25,36,84

Answer 1

Heya !!

Prime factorisation of 548 = 1 ×2 × 2 × 137

Prime factorisation of 12 = 1 ×2 × 2 × 3

Prime factorisation of 45 = 1 × 3 × 3 × 5

Prime factorisation of 25 = 1 × 5 × 5

Prime factorisation of 36 = 1 × 2 × 2 × 3 × 3

And,

Prime factorisation of 84 = 1 × 2 × 2 × 3 × 7.

HCF of 548 , 12 , 45,25, 36 and 84 = 1.

Hope it will help you :-)

Answer 2

Hey!!

We have 548, 12, 45, 25, 36, and 84

Prime factorisation of 548 = 2 × 2 × 137 × 1

Prime factorization of 12 = 2 × 2 × 3 × 1

Prime factorization of 45 = 3 × 3 × 5 × 1

Prime factorisation of 25 = 5 × 5 × 1

Prime factorisation of 36 = 2 × 2 × 3 × 3 × 1

Prime factorisation of 84 = 2 × 2 × 3 × 7 × 1

Therefore HCF [ 548 , 12 , 45, 25, 36 and 84 ] = 1 >>>> Answer

HOPE IT WILL HELPS YOU :-)