Question

Hcf of 566 and 1155 by euclid lemma

Answer 1

hey mate

here is ur answer :-

1155 = 566 x 2 + 23
566= 23x 24 + 14
23 = 14 x 1 +9
14 = 9 x 1 + 5
9 = 5 x 1 + 4
5= 4 x 1 + 1
4 = 1 x 4 + 0

its hcf = 1


I hope it help u

Answer 2

Hello user ...

Solution Given below ☺☺☺
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We have ..
$(566 \: \: and \: \: 1155) \\ \\ using \: \: euclids \: \: division \: \: lemma \: \\ we \: get \\ \\ = > 1155 = 566 \times 2 + 23 \\ = > 566 = 23 \times 24 + 14 \\ = > 23 = 14 \times 1 + 9 \\ = > 14 = 9 \times 1 + 5 \\ = >9 = 5 \times 1 + 4 \\ = > 5 = 4 \times 1 + 1 \\ = > 4 = 1 \times 4 + 0$

Here remainder is become zero .

so the HCF of 566 and 1155 is 1 .

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Hope it's helps you.
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