hcf of 6 and 20 is in the form 6n-22 then value of n
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Answered by
0
Answer:
n=32
Step-by-step explanation:
LCM of 6 ànd 20 is 60
6n-22=60
n-22=60/6=10
n=10+22
n=32
Answered by
0
Answer:
First of all we have to find the HCF of the given numbers and then equate it by the Given hcf in the question which is in the form of an equation
HCF[6,20 ] = 2
6n-22 = 2
6n = 2+22
6n = 24
n = 24 \6
n = 4
Hence , the required value of x is 4 .
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