Question

HCF of 60 80 and 108​

Answer 1

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$Prime \: \: factors \: \: of \: \: 60 = 2 \times 2 \times 3 \times 5 \\Prime \: \: factors \: \: of \: \: 80 = 2 \times 2 \times 2 \times 2 \times 5\\ Prime \: \: factors \: \: of \: \: 108 = 2 \times 2 \times 3 \times 3 \times 3 \\ \\ \\Highest \: Common \: \: Factors \: \: of \: 60,80,108 = 2 \times 2 = 4$

Answer 2

Answer:

• The HFC of 60,80and 108=4

For solution refer to the attachment.

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