Question

Hcf of 620,1430 continued division method

Answer 1

Answer:

10

Step-by-step explanation:

Let us assume that the ‘greatest number’ in the question is ‘x'.

So, if dividing 625 by ‘x' leaves a remainder 5, then 620 will be completely divisible by ‘x'.

Similarly, if dividing 1433 by ‘x' leaves a remainder 3, then 1430 will be completely divisible by ‘x'.

So, ‘x' is the greatest divisor of both 620 and 1430 which means ‘x' is the HCF of 620 and 1430

620 = 2x2x5x31

1430 = 2x5x11x13

The answer is 2 x 5 = 10

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