HCF of 657 and 963 is expressible in the form of 657x + 963y. Find x and y
Attachments:
Answers
Answered by
100
According to Euclid's division lemma
a=bq+r, 0<=r<b
963=657*1+306
657=306*2+45
306=45*6+36
45=36*1+9
36=9*4+0
9=[45-(36*1)]
9=[45-{306-(45*6)}*1]
9=[45-(306*1)+(45*6)]
9=[{657-(306*2)}*(6+1)-306*1]
9=[657*7-306*14-306*1]
9=[657*7-306*15]
9=[657*7-{963-(657*1)}*15]
9=[657*7-963*15+657*15]
9=[657*22-963*15]
9=657x+963y
x = 22, y = (-15)
a=bq+r, 0<=r<b
963=657*1+306
657=306*2+45
306=45*6+36
45=36*1+9
36=9*4+0
9=[45-(36*1)]
9=[45-{306-(45*6)}*1]
9=[45-(306*1)+(45*6)]
9=[{657-(306*2)}*(6+1)-306*1]
9=[657*7-306*14-306*1]
9=[657*7-306*15]
9=[657*7-{963-(657*1)}*15]
9=[657*7-963*15+657*15]
9=[657*22-963*15]
9=657x+963y
x = 22, y = (-15)
Answered by
2
Answer:
x = 22
y= -15
check the steps in the given attachment
Thanks
Attachments:
Similar questions