Math, asked by singhkumarsanjay254, 7 months ago

. HCF of 6abc, 24ab2

, 12a2b is

i) 6ab ii) 6ab2

iii) 6ab2

iv) 6abc​

Answers

Answered by sajal958
5

Answer:

i 6ab

6abc= 2*3*a*b*c

24ab2= 2*2*2*3*a*b*b

common:- 2*3*a*b

therefore 6ab

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