HCF OF 72 ,126,168 BY Using Euclid's division lemma full solution
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Answered by
3
ACCORDING TO EUCLID'S DIVISION LEMMA
HCF (72,126,168) CAN BE FOUND
168 > 126
168 = 126×1 + 42
reminder = 42
quotient = 1
42) 126 ( 3
126
-------
0
THE HCF OF 126 AND 168 IS 3
168 > 72
168 = 72×2 + 24
reminder = 24
quotient = 2
24) 72 ( 3
72
--------
0
HCF OF 72 AND 168 IS 3
HENCE 2 IS THE QUOTIENT SO HCF OF (72,168,126) = 2*3 =6
HCF (72,126,168) CAN BE FOUND
168 > 126
168 = 126×1 + 42
reminder = 42
quotient = 1
42) 126 ( 3
126
-------
0
THE HCF OF 126 AND 168 IS 3
168 > 72
168 = 72×2 + 24
reminder = 24
quotient = 2
24) 72 ( 3
72
--------
0
HCF OF 72 AND 168 IS 3
HENCE 2 IS THE QUOTIENT SO HCF OF (72,168,126) = 2*3 =6
jc48yadav:
no it not right answer is 3024 but I'm not getting how it comes
no will you pls check the question
hcf stands for highest comon factor 6 is the common factor which divides all 3 numbers
HCF is 3024 only
Answered by
1
Step-by-step explanation:
ACCORDING TO EUCLID'S DIVISION LEMMA
HCF (72,126,168) CAN BE FOUND
168 > 126
168 = 126×1 + 42
reminder = 42
quotient = 1
42) 126 ( 3
126
-------
0
THE HCF OF 126 AND 168 IS 3
168 > 72
168 = 72×2 + 24
reminder = 24
quotient = 2
24) 72 ( 3
72
--------
0
HCF OF 72 AND 168 IS 24.
HENCE 2 IS THE QUOTIENT SO HCF OF (72,168,126) = 2×3 =6
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