HCF Of 748, 408, 512......Please rplyy fast
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15
short e technique of getting hcf is factor listing process
748 (factors) - 1,2,4,11,17,22,34,44,68,187,374,748
408 - 1,2,3,4,6,8,12,17,24,34,51,68,102,136,204,408
512 - 1, 2, 4, 8, 16, 32, 64, 128, 256, 512
only one of the prime number repeats above in each and so the hcf of 748, 408, 512 is 2.
748 (factors) - 1,2,4,11,17,22,34,44,68,187,374,748
408 - 1,2,3,4,6,8,12,17,24,34,51,68,102,136,204,408
512 - 1, 2, 4, 8, 16, 32, 64, 128, 256, 512
only one of the prime number repeats above in each and so the hcf of 748, 408, 512 is 2.
Answered by
7
hcf of the 3 numbers is 2
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