Question

HCF of 81,108,135find hcf​

Answer 1

Step-by-step explanation:

81 = 3 × 3 × 3 × 3

108 = 2 × 2 × 3 × 3 × 3

135 = 3 × 3 × 3 × 5

HCF = 3 × 3 × 3

=> 27

Answer 2

Given: The equation is$81,108,\ and\ 135$.

We have to find the HCF$81,108,\ and\ 135$.

We are solving in the following way:

We have,

The equation is$81,108,\ and\ 135$.

The factors of $81$are: $1, 3, 9, 27, 81$

The factors of $108$are: $1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108$

The factors of $135$are: $1, 3, 5, 9, 15, 27, 45, 135$

As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

From the above concept, we can say that the HCF is$27$.

Hence, the HCF of the above numbers is$27$.