Question

HCF of 86,106,212 and 330​

Answer 1

Answer:

86 = 2 × 43

106 = 2 × 53

212 = 2 × 2 × 53

330 = 2 × 2 × 3 × 5 × 5 × 11

HCF of 86, 106, 212 and 330 = 2.

Answer 2

To find : HCF of  $86, 106 ,212\ and \ 330$

Solution :

• HCF is the highest common factor also called as greatest common divisor ,( GCD ).

• To find HCF of  we find prime factors of these numbers .

• Prime factors of $86 = 2\times 43$

• Prime factors of $106=2\times 53$

• Prime factors of $212 = 2\times 2\times 53$

• Prime factors of $330 = 2\times3\times5\times11$

• HCF of $86, 106 ,212\ and \ 330$=  $2$

Hence , HCF of $86, 106 ,212\ and \ 330$  is $2$ .