HCF of a^2m^4 and a^4 m^2
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Answered by
0
Answer:
Step-by-step explanation:
4am3 = 4am3
2am3 + 4a2m2 = 2am2(m + 2a); [taking the common factor 2am^2 from both the terms].
Therefore, the H.C.F. of 4am3 and 2am3 + 4a2m2 = 2am2
Answered by
3
Answer:
a^2m^2
Step-by-step explanation:
a^2m^4 = a×a×m×m×m×m
a^4m^2 = a×a×a×a×m×m
we can see that the HCF comes to be a×a×m×m
which can be written as a^2m^2
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