Question

HCF of (a2+7a+18) , (a2+10a+9) and (a+9)​

Answer 1

Answer:

Find the H.C.F. and L.C.M. of the expressions a2 – 12a + 35 and a2 – 8a + 7 by factorization.

Solution:

First expression = a2 – 12a + 35

= a2 – 7a – 5a + 35

= a(a – 7) – 5(a – 7)

= (a – 7) (a – 5)

Step-by-step explanation:

Second expression = a2 – 8a + 7

= a2 – 7a – a + 7

= a(a – 7) – 1(a – 7)

= (a – 7) (a – 1)

Therefore, the H.C.F. = (a – 7) and L.C.M. = (a – 7) (a – 5) (a – 1)

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