Question

HCF of a2x
2
+ a2x
3
+ ax4

Answer 1

Answer:

Step-by-step explanation:

The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

To find G.C.D of ax2, a2x3 and a4x, let us first write down factors of each term.

Factorization of ax2 = a × x × x

Factorization of a2x3 = a × a × x × x × x

Factorization of a4x = a × a × a × a × x

Find the factors that these three lists share in common.

Factors of ax2 = a, x, x

Factors of a2x3 = a, a, x, x, x

Factors of a4x = a, a, a, a, x

Common factors that are found in these three terms is a and x.

By multiplying these factors, we get

a × x = ax

Thus, the gcd of ax2, a2x3 and a4x is ax.

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Answer 2

Answer:

it's solutions

Step-by-step explanation:

step by step