Question

Hcf of b3-a3 and b4-a4

Answer 1

Answer:

b-a

Step-by-step explanation:

b^3-a^3= (b-a) ( b^2-ba+ a^2)

b^4-a^4=(b^2)^2-(a^2)^2

=(b^2+a^2)(b^2-a^2)

=(b^2+a^2)(b+a)(b-a)

So the HCF will be (b-a)