HCF of co prime 4 and 15 was found as follows by factorisation :
4 = 2 x2 and 15 = 3 x 5 since there is no common prime factors , so HCF of 4 and 15 is 0 . Is the answer correct ? If not , What is the correct HCF ?
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4=2×2 and 15=3×5 Since there is no common prime factor, so HCF of 4 and 15 is 0. Since there is no common prime factor , so HCF of 4 and 15 is 0.
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