Math, asked by psaidarshan, 1 month ago

HCF of factors of 3a(3b + 2) is

Answers

Answered by rahmantranslator

2

Answer:

Find out the H.C.F. of a2b + ab2 and a2c + abc by factorization.

Solution:

First expression = a2b + ab2

= ab(a + b)

= a × b × (a + b)

Step-by-step explanation:

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