hcf of following - 6265 & 76254, 2825 & 70625, 8286 & 101592
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All the factors written are prime.
1) 6265 and 76254
6265 = 5×7×179
76254 = 2×3×71×179
So, HCF = 179
2) 2825 and 70625
2825 = 5×5×113
70625 = 5×5×5×5×113
So, HCF = 5×5×113
So, HCF = 2825
3) 8286 and 101592
8286 = 2×3×1381
101592 = 2×2×2×3×3×17×83
So, HCF = 2×3
So, HCF = 6
1) 6265 and 76254
6265 = 5×7×179
76254 = 2×3×71×179
So, HCF = 179
2) 2825 and 70625
2825 = 5×5×113
70625 = 5×5×5×5×113
So, HCF = 5×5×113
So, HCF = 2825
3) 8286 and 101592
8286 = 2×3×1381
101592 = 2×2×2×3×3×17×83
So, HCF = 2×3
So, HCF = 6
QGP:
You might be wondering how I factorised such huge numbers. I didn't. I made a computer program which gives me the prime factors
Then I also made an HCF program to verify my answer
ohhhh wow
hats off to you
Thank you.
Thanks for marking it as brainliest
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