Math, asked by nemeeshasen832, 18 days ago

hcf of the following expression: a^2-1,a^3-1,a^2+a-2 ​

Answers

Answered by y2krahulsingh
1

Answer:

First,

a^2 - 1 = (a)^2 - (1)^2

= (a + 1) (a - 1)

Second,

a^3 - 1 = (a)^3 - (1)^3

= (a - 1) (a^2 + a + 1)

Third,

a^2 + a - 2 = a^2 + (2a - a) -2

= a^2 + 2a - a - 2

= a (a + 2) - 1 (a + 2)

= (a - 1) (a + 2)

Therefore, the required H.C.F is (a - 1)

Answer :- H.C.F = ( a - 1)

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