HCF of the numbers 3^7×5^3×2^4 and 3^2×7^4×2^8
Answers
Answer:
3×7×5×3×2×4and3×2×7×4×2×8
Step-by-step explanation:
3×2×7×4=168
Answer:
HCF of 3⁷×5³×2⁴ and 3²×7⁴×2⁸ = 144
Step-by-step explanation:
Given numbers are 3⁷×5³×2⁴ and 3²×7⁴×2⁸
To find,
The HCF of the given two numbers
Solution:
HCF of two numbers is defined as the highest factor which divides both the numbers
In the given numbers 3⁷×5³×2⁴ and 3²×7⁴×2⁸
The highest factor of 3, which divides both the numbers is 3²
The highest factor of 5, which divides both the numbers is 1 since 5 is not a factor of the second number
The highest factor of 2, which divides both the numbers is 2⁴
The highest factor of 7, which divides both the numbers is 1 since 7 is not a factor of the first number
Hence the highest common factor of both the numbers = 3²×2⁴
= 9×16
= 144
∴HCF of 3⁷×5³×2⁴ and 3²×7⁴×2⁸ = 144
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