HCF of the terms of the expression x⁴y + 3 x²y ²-6xy³is
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Given:
Terms are : x⁴y , 3x²y² , 6xy³
To find:
HCF of the terms of the expression x⁴y + 3x²y ²- 6xy³.
Solution:
x⁴y = x × x × x × x × y
3x²y² = 3 × x × x × y × y
6xy = 2 × 3 × x × y
Only xy is common in all the three terms.
Therefore, HCF = x × y = xy
So, HCF is xy
Question for practice:
Find the HCF of x³y² , x²y³ and x⁴y⁴.
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