Question

HCF of two consecutive even number is
(a) 0
(b) 1
(c) 4
(d) 2​

Answer 1

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Here's your answer

The highest common factor is 2. They don't have any other factor than 1 common to them. Hence HCF of two consecutive even numbers is 2.

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Answer 2

Step-by-step explanation:

Consider two consecutive even numbers. They are of the form 2n,2n+2 for some integer n

2n=2×n

2n+2=2×(n+1)

The numbers n,n+1, being two consecutive integers, are relatively prime

They do not have any factor other than 1 common to them.

Hence HCF of two consecutive even numbers is 2.

So the correct answer is option D

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