hcf of two no is 23 and their lcm is 1449 if the one of the no is 161 then find other no
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HCF = 23
LCM = 1449
Let the two numbers be a and b. Let a = 161. We have to find b.
We know that
HCF(a,b) * LCM(a,b) = a*b
∴23 * 1449 = 161 * b
∴23*1449/161 = b
∴b = 23*9
∴b = 207
Thus, the other number is 207.
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