hcf of two no is 67 and sum is 670 . how many such pairs possible
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These two numbers must be multiples of 67.
Multiples of 67 :
67 × 1 = 67
67 × 2 = 134
67 × 3 = 201
67 × 4 = 268
67 × 5 = 335
67 × 6 = 402
67 × 7 = 469
67 × 8 = 536
67 × 9 = 603
67 × 10 = 670
The sums are as follows :
1) 603 + 67 = 670
2) 536 + 134 = 670
3) 469 + 201 = 670
4) 402 + 268 = 670
Answered by
0
Answer:
hese two numbers must be multiples of 67.
Multiples of 67 :
67 × 1 = 67
67 × 2 = 134
67 × 3 = 201
67 × 4 = 268
67 × 5 = 335
67 × 6 = 402
67 × 7 = 469
67 × 8 = 536
67 × 9 = 603
67 × 10 = 670
The sums are as follows :
1) 603 + 67 = 670
2) 536 + 134 = 670
3) 469 + 201 = 670
4) 402 + 268 = 670
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