hcf of two number is 4 and factor of lcm is 5,7 then find the smallest number
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Since the L.C.M. has three factors 4, 5 and 7 and H.C.F. of a and b is 4. So, 4 is a factor of both the numbers a and b. Also, 5 is a factor of one number and 7 is a factor of a=4×5=20,b=4×7=28. Thus, the two numbers are 20 and 28., and so the smaller number is 20.
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Answer:
Since the L.C.M. has three factors 4, 5 and 7 and H.C.F. of a and b is 4. So, 4 is a factor of both the numbers a and b. Also, 5 is a factor of one number and 7 is a factor of a=4×5=20,b=4×7=28. Thus, the two numbers are 20 and 28., and so the smaller number is 20.
Step-by-step explanation:
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