Hcf of two number is28 and their lcm is 336 if one number is 112 then find other
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Solution :
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If a , b are two numbers and
their HCF = h and LCM = l then
a × b = h × l
***************************************
Now ,
a = 112 , b = ?
h = 28 , l = 336
a × b = h × l
=> b = ( h × l )/a
=> b = ( 28 × 336 )/112
= 28 × 3
= 84
Therefore ,
Second Number = b = 84
••••
***************************************
If a , b are two numbers and
their HCF = h and LCM = l then
a × b = h × l
***************************************
Now ,
a = 112 , b = ?
h = 28 , l = 336
a × b = h × l
=> b = ( h × l )/a
=> b = ( 28 × 336 )/112
= 28 × 3
= 84
Therefore ,
Second Number = b = 84
••••
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