hcf of two numbers, each consisting of four digits, is 103 and their lcm is 19261. the difference of the numbers is (a) 6/8 (b) 5/9 (c) 5/8 (d) 4/8
Answers
Answer:
618
Step-by-step explanation:
Given hcf of two numbers, each consisting of four digits, is 103 and their lcm is 19261. the difference of the numbers is
Let the two numbers be x and y and two numbers will be 103 x and 103 y
since the numbers x and y are prime to each other.
Now we know that according to question
103 xy = lcm that is 19261
So 103 xy = 19261
xy = 19261 / 103
xy = 187
So x will be 11 and y will be 17 since 11 x 17 = 187
Now 103 x 11 = 1133 and 103 x 17 = 1751
So the numbers are 1133 and 1751. Now the difference of the numbers are 1751 - 1133 = 618
Answer:
hcf of two numbers, each consisting of four digits, is 103 and their lcm is 19261. the difference of the numbers is 618
Step-by-step explanation:
Let one number be 103a & another number 103b
as 103a & 103b are 4 digit numbers so
98 > a , b > 9 a & b are distinct number
103a & 103b = LCM * HCF
=> 103 a * 103 b = 103 * 19261
=> ab = 187
a & b can be 11 & 17
Difference between numbers
103 * (17 -11)
= 103 * 6
= 618
option a is correct