Question

HCF of two numbers is 20 and their LCM
is 120. If one number is 60 find the other.​

Answer 1

$\tt \large \blue{Solution:-}$

$\: \: \: \: \: \: \tt{HCF \: of \: two \: numbers \: is \: 20 } \\ \: \: \: \: \: \: \tt{and \: their \: LCM \: is \: 120.}$

$\tt \blue{A/Q,}$

$\: \: \: \: \: \: \tt{Let \: the \: One \: no \: be \: N_1 \: and } \\ \: \: \: \: \: \: \tt{Other \: no \: be \: N_2.}$

$\: \: \: \: \: \: \tt{H.C.F \times L.C.M= Product \: of \: two \: no.}$

$\: \: \: \: \: \: \tt{20 \times 120 = N_1 \times N_2.}$

$\: \: \: \: \: \: \tt{20 \times 120 = 60\times N_2.}$

$\: \: \: \: \: \: \tt{ \frac{20 \times 12 \cancel{0}}{6 \cancel{0}} = N_2.}$

$\: \: \: \: \: \: \tt{ \frac{20 \times \cancel{12} }{ \cancel6 } = N_2.}$

$\: \: \: \: \: \: \tt{ 20 \times 2 = N_2.}$

$\: \: \: \: \: \: \tt{ 40= N_2.}$

$\tt{Therefore, the \: value \: of \: Other } \\ \tt{ no \: be \: \red{40}.}$

Answer 2

Answer:

40

Step-by-step explanation:

let the first and second number be a and b

so 20*120= product of two numbers

a=60

20*120/60

=40

b=40