Question

Hcf of two numbers is 23 and their lcm is 1449 .if one of the numbers is 161. Then find the other number.​

Answer 1

HCF = 23

LCM = 1449

Let the two numbers be a and b. Let a = 161. We have to find b.We know that HCF(a,b) * LCM(a,b) = a*b∴23 * 1449 = 161 * b∴23*1449/161 = b∴b = 23*9∴b = 207Thus, the other number is 207.

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Answer 2

Answer:

let the numbers be Xand Y

X=161 Y=?

H.C.F =23

L.C.M =1449

According to the problem,

H.C.F*L.C.M=a*b

23*1449=161*b

161b=23*1449

b=1449/161*23

b=9*23( when we cancel

1449/161 is 9)

b=207

Therefore, the other number is 207