Question

HCF of two numbers is 24 and their LCM is 1344.if the difference between numbers is 80,find the sum

Answer 1

Let the two numbers be x and y ,
HCF = 24
LCM = 1344

HCF × LCM = x×y
24×1344 = xy
xy = 32256

(x-y) = 80
x = 80+y

(80+y)×y = 32256
y^2 +80y -32256 = 0
y^2 +224y -144y -32256 = 0
y(y+224) -144(y+224) =0

y = 114 & -224
x = 80+114
x = 194

x+y = 194+80
= 274


hope this helped ..... -- !