Question

HCF of two numbers is 42 if the product of the numbers is 15876, then possible number of such pairs is_______

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

You have two numbers that are divisible by 42. We can write these as 42a and 42b for a,b coprime (can you see why?). Their product is 15876, so we have

422ab=15876⟺ab=9.

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Answer 2

Answer:

1

Step-by-step explanation:

You have two numbers that are divisible by 42. We can write these as 42a and 42b for a,b coprime (can you see why?). Their product is 15876, so we have

422ab=15876⟺ab=9.

It it now enough to determine which a,b satisfy ab=9, where a and b are coprime.

Therefore, required possible pair of values of a and b which are prime to each other is (1, 9)

Thus, the required number is (1,9).

Hence, the number of possible pairs is 1.

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