HCF of two numbersis 27 and their LCM is 162, if one of the number is 54, what is the other number
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Answer:
HCF×LCM=Product of the two numbers
=>27×162=54 × x
=>x=27×162/54
=>x=81
Answered by
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Given:
HCF=27
LCM= 162
First number = 54
To find:
Second number = ?
Solution:
Let the other number be x
LCM×HCF= Product of two numbers
162×27=54×x
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