HCF of two polynomials p(x)= (x-3) (x^2+x-2) and q(x)= x^2 -5x+6 is (x-3) then their lcm is
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Answer:
Step-by-step explanation:
given,
p(x) = (x - 3)(x² + x - 2)
q(x) = x² - 5x + 6
HCF = x - 3
Method 1:
We know that product of two numbers = HCF * LCm
=> (x - 3)(x² + x - 2) * (x² - 5x + 6) = (x - 3) * LCM
=> (x - 3 )(x + 2) (x - 1) * (x -3)(x -2) = (x - 3) * LCM
=> LCM = (x + 2) (x - 1) (x -3)(x -2)
Method 2:
p(x) = (x - 3)(x² + x - 2)
Factors are (x - 3 )(x + 2) (x - 1)
q(x) = x² - 5x + 6
Factors are (x -3)(x -2 )
Thus LCM is (x -3) ( x-2)(x+2)(x-1)
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