Math, asked by ankitjangra868, 17 days ago

hcf of x^2-ax-(a+1) and ax^2-x-(a+1)​

Answers

Answered by amitnrw
2

Given :  x²-ax-(a+1)   and   ax²-x-(a+1)​

To Find : HCF

Solution:

x²-ax-(a+1)

=x²  - (a + 1)x + x - (a + 1)

= x(x  - a - 1) +  1(x - a - 1)

= (x + 1)(x - (a + 1))

ax²-x-(a+1)​

ax²  + ax - (a + 1)x - (a + 1)

= ax(x + 1) - (a + 1)(x + 1)

= (x + 1) (ax - (a + 1))

Hence HCF = (x + 1)

HCF Highest common factor is highest power polynomial and  

largest power numeric coefficient expression which can divide all the expressions.

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Answered by мααɴѕí
2

Answer:

x3 + (a +b)x2 + (ab + 1)x + b

= x3 + (a +b)x2 + abx + x + b

= x [x2 + (a + b)x + ab] + (x + b)

= x (x + a) (x + b) + (x + b)

= (x + b) [x (x + a) + 1]

= (x + b) (x2 + ax + a)

x 3 + 2ax 2 + (a 2 + 1)x + a

= x3 + 2ax2 + a 2 x + x + a

= x (x 2 + 2ax + a 2 ) + (x + a)

= x (x + a) (x + a) + (x + a)

= (x + a) [x (x + a) + 1]

= (x + a) (x 2 + ax + 1)

Common factor between the two polynomials = x 2 + ax + 1

∴ HCF = x 2 + ax +1

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