Math, asked by surabhiver123, 1 year ago

Hcf of (x^3-3x+2) and (x^2-4x+3)

Answers

Answered by Anonymous
3
Heya buddy


Here


1st expression
= (x^2 -3x+2)
=x^2 - 2x-x+2
=x(x-2)-1(x-2)
=(x-1)(x-2)


2nd expression
= (x^2-4x+3)
=x^2 - 3x-x+3
=x(x-3)-1(x-3)
=(x-1)(x-3)

So,
HCF
=(x-1)

Hope it helps

And plz check ur question once,in first expression, there will be x^2, not x^3......
Similar questions