Hcf of x³+1 and x²-1 will be
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f(x)=(x² -1)/(x³ -1), factorize the given function
Because [x²-1=(x-1)(x+1),(x³-1)=(x-1)(x²+x+1)]
»f(x)=(x-1)(x+1)/(x-1)(x²+x+1),
and put x=1we get, f(x)=(1+1)/(1²+1+1)=2/3Ans
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