Question

hcf program in c language
​

Answer 1

#include <stdio.h>

long gcd(long, long);

int main() {

long x, y, hcf, lcm;

printf("Enter two integers\n");

scanf("%ld%ld", &x, &y);

hcf = gcd(x, y);

lcm = (x*y)/hcf;

printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);

printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);

return 0;

}

long gcd(long x, long y) {

if (x == 0) {

return y;

}

while (y != 0) {

if (x > y) {

x = x - y;

}

else {

y = y - x;

}

}

return x;

}