Question

Hcf72and 102 in euclids division lemma

Answer 1

Answer :-

$\\ \begin{array}{cc} \sf 72 )&\sf \ \: \: \: \: \: \: \: 120 \: \: \: \: \: \: (1\\&\sf 72 \\ \cline{2-2}& \sf \ 48 \\ \cline{2-2} \end{array}\\\\\\ \sf Divisor \implies 72\\ \\ \sf Quotient \implies \: 1\\\\ \sf \: Remainder \implies 48$

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$\: \\ \begin{array}{cc}\sf 48 )&\sf \ \: \: \: \: \: \: \: 72 \: \: \: \: \: \: (1\\&\sf 48 \\ \cline{2-2}& \sf \ 24 \\ \cline{2-2} \end{array}\\\\\\ \sf Divisor \implies 48\\ \\ \sf Quotient \implies \: 1\\\\ \sf \: Remainder \implies 24$

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$\: \\ \begin{array}{cc} \sf 24 )&\sf \ \: \: \: \: \: \: \: 48 \: \: \: \: \: \: (1\\&\sf 48 \\ \cline{2-2}& \sf \ 0\\ \cline{2-2} \end{array}\\\\\\ \sf Divisor \implies 24\\ \\ \sf Quotient \implies \: 2\\\\ \sf \: Remainder \implies \: 0$

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➦ 120 = 72 x 1 + 48

➦ 72 = 48 x 1 + 24

➦ 48 = 24 x 2 + 0

$\therefore\underline{ \underline{ \frak{ \green{\:Hcf \: 72 \: and \: 102 \: in \: euclids \: division \: lemma \: is \: 0}}}}$