HCFand LCMof two numbers is 9 and 108 respectively. If one of the numbers is 36, find the other number.
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L.C.M( a , b)* H.C.F (a, b) = a * b
here , L.C.M(a , b) = 108
H.C.F(a, b ) = 9
a = 36
therefore b = 108 * 9 / 36 = 27
therefore other number is 27
here , L.C.M(a , b) = 108
H.C.F(a, b ) = 9
a = 36
therefore b = 108 * 9 / 36 = 27
therefore other number is 27
swapy2911:
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Answered by
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other no=(hcf*lcm)/first no
. =(9*108)/36
=972/36
=27
. =(9*108)/36
=972/36
=27
plz mark my ans as brainliest
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