Question

HCFis 5 and LCM is 60.one no is is 15 then what is the second no?

Answer 1

$\huge{ \sf{ \green{ \mid{ \underline{ \overline{ \red{work \: out...}}}}}}}$

$\large{ \bold{ \to \: u \: must \: know...}} \\ \large{ \green{ \boxed{ \red{ \to \: hcf \times lcm = product \: of \: no.s}}}}$

$\large{ \to \: \: given \: hcf = 5} \\ \: \: \: \: \: \: \: \: \: \large{ and \: lcm = 60} \\ \large{ \green{ \to \: one \: of \: the \: no.s = 15}} \\ \: \: \: \: \: \: \: \: \large{ \green{let \: othe \: no. \: be \: \red{ x}}} \\ \large{ then \: hcf \times lcm = product \: of \: no.s} \\ = > \large{ 5 \times 60 = 15 \times x} \\ \large{ = > x = \frac{5 \times 60}{15} } \\ \large{ = > x = 5 \times 4} \\ = > \large{ \red{x = 20}} (\blue{ \mathfrak{answer...}})$

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Answer 2

$\huge\bigstar\blue{Answer}$

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Given :-

• HCF = 5

• LCM = 60

• One number = 15

To Find :-

• Other number

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Let second number be x

We know that HCF × LCM = product of two numbers

Then ,

5 × 60 = x × 15

= = > 300 = 15x

= = > x = 300/15

= = > x = 20

Hence, 2nd number is 20

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