HCl is added to a hydrocarbon 'A',(c⁴h⁸)to give a compound 'B' which on hydrolysis with aqueous alkali forms a tertiary alcohol 'C'(C⁴H¹⁰O) identify 'A' ,'B','C'.
Answers
The reaction is given below.
Explanation:
The compound (c⁴h⁸) is 2-methylpropene.
When it reacts with hydro-chloric acid it forms 2-methyl-2-chloropropane.
The reaction is given below.
Its structural formula is:
CH3 CH3 CH3
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CH3 - C = CH2 + HCl ----> CH3 - C - CH3 + H2O ----> CH3 - C - CH3
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Cl OH
The resulting product in the first step is 2-methyl-2-chloropropane and in the second step when it reacts with water to form 2-methyl-2-propanol.