Question

HCL is sold commercialy at 12 M solution. how many moles are in 300 ml of 12M solution ​

Answer 1

Answer:

M = mass/molar mass × 1000/volume

M = moles × 1000/volume(ml)

12 = moles × 1000/300

Moles = 12×3/10

Moles = 36/10 = 3.6

So 3.6 moles are in 12 M solution

Hope it helps.....

Answer 2

Answer:

300 ml = 300/1000 L = 0.3 L

Now, Molarity of HCl sol. = 12 M

therefore, 12 moles of HCL are present in 1 L of sol.

Now, In 0.3 L, no. of moles present will be 0.3 × 12 = 3.6 moles.