(HCV) The force on a particle of mass 10 g is F =
(101 + 5j) N. If it starts from rest, what would be its
position vector at time t = 5 s will be
(a) 10500 + 6250ſ (b) 12500î + 60009
(c) 12500î + 3250ġ (d) 125001 + 6250j
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Answer:
D) 12500Î + 6250j
Explanation:
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