Question

hdFg haldiya leIlaulafehn​

Answer 1

Step-by-step explanation:

Let 45=a2−b2 , then 45=(a+b)(a−b) . Also, a+b and a−b have the same parity. So we need to find two odd or two even factors of 45 .

We have that 45=45×1=15×3=9×5 .

For 45×1 , we have a+b=45,a−b=1 . Adding both expressions we get 2a=46 , a=23 , and b=22 . Effectively 45=529−484 .

For 15×3 we have a=9 , and b=6 , for 45=81−36.

Finally for 9×5 we get a=7 , b=2 , for 45=49−4

Answer 2

Answer:

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