He (2); Ne (10) and Ar (18) belong to the same group in the modern periodic table (a) Name the period of each element. (b) Write the electronic configuration of each element.
Answers
Answered by
8
1)
Helium(He) = Period 1
Neon(N) = Period 2
Argon(Ar) = Period 3
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2)
Helium :
Atomic number = 2.
No: of protons =2
No: of electrons = 2
Electronic configuration = 2 , 0
Neon:
Atomic number = 10
No: of protons =10
No: of electrons = 10
Electronic configuration = 2 , 8
Argon:
Atomic number = 18
No: of protons = 18
No: of electrons = 18
Electronic configuration = 2 ,8 , 8
Helium(He) = Period 1
Neon(N) = Period 2
Argon(Ar) = Period 3
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2)
Helium :
Atomic number = 2.
No: of protons =2
No: of electrons = 2
Electronic configuration = 2 , 0
Neon:
Atomic number = 10
No: of protons =10
No: of electrons = 10
Electronic configuration = 2 , 8
Argon:
Atomic number = 18
No: of protons = 18
No: of electrons = 18
Electronic configuration = 2 ,8 , 8
Answered by
10
hai friend,
here is your answer
Helium(He) :-
atomic number =2
mass number=4
period number =1
electronic configuration =1s²
Neon(Ne) :-
atomic number =10
mass number=20
period number =2
electronic configuration =1s²2s²2p^6
Argon(Ar) :-
atomic number =18
mass number=40
period number =3
electronic configuration = 1s²2s²2p^63s²3p^6
hope helped:)
here is your answer
Helium(He) :-
atomic number =2
mass number=4
period number =1
electronic configuration =1s²
Neon(Ne) :-
atomic number =10
mass number=20
period number =2
electronic configuration =1s²2s²2p^6
Argon(Ar) :-
atomic number =18
mass number=40
period number =3
electronic configuration = 1s²2s²2p^63s²3p^6
hope helped:)
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